Question 1 Show Answers a) Given — $t = 3.13$ s b) $40.2$ m Question 2 Show Answers a) $t = 3.10$ s b) $h = 0.734$ m c) (i) $23.7$ ms⁻¹ c) (ii) $39.1°$ below the horizontal Question 3 Show Answers a) Maximum height $= 52.7$ m
Area of a sector $= \dfrac{1}{2}r^2\theta$ Arc length $= r\theta$ $\theta$ must be in radians Degrees to radians: multiply by $\pi$, divide by $180$ Radians to degrees: multiply by $180$, divide by $\pi$ Question 1 Show Answers a) $3\pi$ cm b) $5\pi$ cm c)
GCSE Maths | Algebra Collecting like terms $$3a + 2b + 4a + b$$ $$= (3a+4a) + (2b+b)$$ $$= 7a + 3b$$ Question 1 (a) $3a+2b+4a+b$ (b) $7y+5y+2h+2h$ (c) $g+8a+2a+g$ (d) $7m+7p+8m+p+2p$ (e) $9e+2+e+2$ (f) $4+3a+2a+8$ (g)
What is the sine rule? a/sin(A) = b/sin(B) sin(A)/a = sin(B)/b Question 1 - finding a length using the sine rule Show Answers a) $x = 6.39$ cm b) $x = 6.65$ cm c) $x = 60.5$ mm Question 2 - finding an angle using the
Square numbers: $1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144$ Cube numbers: $1, 8, 27, 64, 125$ Powers of 4: $1, 16, 81$ Worked Example $(\sqrt{10})^2 = 10$ Question 1 a) $(\sqrt{15})^2$ b) $(\sqrt{2})^2$ c) $(\sqrt{20})^2$ d) $(\sqrt{11}
To integrate: raise the power by one, then divide the coefficient by the new power. $\displaystyle\int ax^n \, dx = \frac{a}{n+1}x^{n+1} + C$ Using limits gives the area between the curve and the $x$-axis. Question 1 Integrate the following expressions with respect to $x$
Simple Ratios Worked Example Share £40 in the ratio 3:5 $3 : 5 \quad (8)$ $? : ? \quad (40)$ $sf = 40 \div 8 = 5$ $3 \times 5 = 15, \quad 5 \times 5 = 25$ Question 1 a) Share £20 in the ratio 2:3 b) Share 15cm in the ratio 1:2 c)
Final value = original value $\times$ multiplier$^{\text{(number of years)}}$ Worked Example £1000 is invested at 4% per year for 3 years. Multiplier $= 1.04$ Final value $= 1000 \times 1.04^3 = £1124.86$ Question 1 Find the total value after the given number of years, to the nearest penny.
Percentage change $= \dfrac{\text{new} - \text{old}}{\text{old}} \times 100$ Worked Example Original: 60, New: 72 Percentage change $= \dfrac{72-60}{60} \times 100 = \dfrac{12}{60}\times 100 = 20\%$ increase Question 1 Calculate the percentage change. a) Original: 50, New: 65 b) Original: 80, New: 68 c) Original:
Question 1 Q12 - Edexcel AS-Level Maths Paper 1 June 2018 Question 2 Q12 - Edexcel AS-Level Maths Paper 1 June 2019 Question 3 Q9 - Edexcel AS-Level Maths Paper 1 June 2020 Question 4 Q12 - Edexcel AS-Level Maths Paper 1 June 2021 Question 5 Edexcel AS-Level Maths
Rules of Indices $x^{\frac{1}{n}} = \sqrt[n]{x}$ $x^{\frac{m}{n}} = \left(\sqrt[n]{x}\right)^m$ $x^{-n} = \dfrac{1}{x^n}$ Question 1 Solve each equation. a) $x^{\frac{1}{2}} = 6$ b) $x^{\frac{1}{3}} = 5$ c) $x^{-\frac{1}{2}} = 2$ d)
Question 1 Q4 - Edexcel A-Level Maths Paper 2 June 2018 Question 2 Q11 - Edexcel A-Level Maths Paper 1 June 2019 Question 3 Q5 - Edexcel A-Level Maths Paper 1 June 2020 Question 4 Q13 - Edexcel A-Level Maths Paper 1 June 2020 Question 5 Q15 - Edexcel A-Level